Boron 8 nucleus decay form
Nuclear structure of

Boron 8
5p2nB7p em0.32 zeps3/2-5 = 3p+2 - (3n)
5p3nB8b+770 ms2+5 = 2p+3 - (2n)
5p4nB9p+2He em8x10-19 s3/2-5 = 1p+4 - (1n)
5p5nB1019.8 %stable3+5 = 3+2
5p6nB1180.2 %stable3/2-5 = 1+4 + (1n)
5p7nB12e em, 3He em20.20 ms1+5 = 2+3 + (2n)
5p8nB13e em17.33 ms3/2-5 = 3+2 + (3n)

(half life = 770 ms). Move mouse over image for B8 nucleus transition form.

Blue toruses = 8 protons
Red toruses = 3 nuclear electrons

Atomic number of B (5) = protons (8) - nuclear electrons (3)

Boron 8 transform by electron capture (from light !) of B8 nucleus transition form and Be8 nucleus generated (half life = 67 as).
The electron comes from a photon pair production and the rest of a positron emanated.

Be8 nucleus shortly decay further by splitting of Beryllium 8 into two He4 particles.

Click on image for Be8 nucleus decay.

Photon model of light
Structures of atomic nuclei

Repulsive magnetic forces act between two half of the B8 nucleus. Decay of Boron 8 forming matastable Berillium 8, He4 emission through Berillium 6 results in alpha particles, He4. It may be interesting if b+ isotopes would lights up with appropriate vawelengths of gamma photon. May it be used for decontamination of radioactive isotopes?

Boron 7 nucleus Boron 9 nucleus