Boron 9 destabilized nuclear structure
Nuclear structure of

Boron 9
.ooOOoo.
5p2nB7p em0.32 zeps3/2-5 = 3p+2 - (3n)
5p3nB8b+770 ms2+5 = 2p+3 - (2n)
5p4nB9p+2He em8x10-19 s3/2-5 = 1p+4 - (1n)
5p5nB1019.8 %stable3+5 = 3+2
5p6nB1180.2 %stable3/2-5 = 1+4 + (1n)
5p7nB12e em, 3He em20.20 ms1+5 = 2+3 + (2n)
5p8nB13e em17.33 ms3/2-5 = 3+2 + (3n)
...
 

(half life = 8x10-19 s). Move mouse on image for Boron 9 destabilized form.

Blue toruses = 9 protons
Red toruses = 4 nuclear electrons

Atomic number of B (5) = protons (9) - nuclear electrons (4)

Boron 9 decomposes by proton emission (100%) with double alpha decay as
central proton of Boron 9 destabilized and forms two He4 nucleus (alpha particles).

After proton emission, the two alpha particles liberated.

See Be8 decay (half life = 6.7x10-17 s), two alpha particles are not stable.


Structures of atomic nuclei
Photon model of light

Boron 9 and B9 isotopes nuclear structure and decomposition of nuclear Boron9 to proton and two alpha particles decay mechanism of decomposition


Boron 8 nucleus Boron 10 nucleus

B7B8B9B10B11B12B13B14B15B16B17

HHeLiBeBCNOFNe
NaMgSiSArCaFeNiNdPb