Helium 10 nucleus and metastable neutrons
Nuclear structure of

Helium 10
2p1nHe30.000137 %stable1/2+2 = p+1 - (1n)
2p2nHe499.999863%stable0+2 = 2
2p3nHe5n em7x10-22 s3/2-2 = 1+1 + (1n)
2p4nHe6e em806.7 ms0+2 = 1+1 + (2n)
2p5nHe7n em2.9x10-21 s3/2-2 = 1+1 + (3n)
2p6nHe8e em119.0 ms0+2 = 2 + (4n)
2p7nHe9n em7 zs1/2-#2 = 1+1 + (5n)
2p8nHe102n em2.68 zeps0+2 = 2 + (6n)

(half life = 2.68 zs). Symmetry of proton-electron toruses: T n n n n T

Blue toruses = 10 protons
Red toruses = 8 nuclear electrons

Atomic number of He (2) = protons (10) - nuclear electrons (8)

Helium 10 decays by 2 neutron emission of Helium 10 neutron excess to Helium 8

Helium 8 decays by electron emission (from the left position) of Helium 8 destabilized, decay form to Lithium 8.

Lithium 8 decays by electron emission of Lithium 8 destabilized form through Be8 producing two He4 nucleus (stable).

(The neutrons and the subsequent electron emission really happens from the end of the nuclear nanotube, NOT from the central position. Im just depict central neutrons for the sake of picturesque symmetry.)

Click on image for Helium 8 nucleus

Yin-yang model of photon and matter
Structures of atomic nuclei of elements

Helium 9 nucleus Lithium 4 nucleus



Helium 10 double neutron emission and mechanism of He10 isotope decay. The subsequent electron emission of destabilized He8 produce Li8 which emits an electron and the Be8 split into two He4 alpha particles.