Oxygen 17 nuclear structure
Nuclear structure of

Nitrogen 17
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7p3nN10200 yoctos2-7 = 4p+3 - (4n)
7p4nN11p em590 ys1/2+7 = 3p+4 - (3n)
7p5nN12b+11.000 ms1+7 = 2p+5 - (2n)
7p6nN13b+9.965 min1/2-7 = 1p+6 - (1n)
7p7nN1499.634%stable1+7 = 4+3
7p8nN150.366%stable1/2-7 = 1+6 + (1n)
7p9nN16e em7.13 s2-7 = 2+5 + (2n)
7p10nN17e em4.173 s1/2-7 = 3+4 + (3n)
...
 

(half life = 4.173 s). Move mouse on image for transitional Oxygen 17 nucleus.

Blue toruses = 17 protons
Red toruses = 10 nuclear electrons

Atomic number of N (7) = protons (17) - nuclear electrons (10)

Nitrogen 17 decays by electron emission of Nitrogen 17 to transitional Oxygen 17 and

subsequently a neutron emission of transitional (activated) Oxygen 17 forming Oxygen 16 stable nucleus.

In reality the electron and the subsequently emitted neutron can liberates only from one of the end position of proton nanotube (not indicated).


Yin-yang photon model of light
Nuclear symmetry,       Nuclear structure of elements
Nuclear properties

Nitrogen 17 nuclear structure. Decay of N17 isotope nucleus electron irradiation and neutron emission decay transform to oxygen 16 stable isotope nucleus


Nitrogen 16 nucleus Oxygen 12 nucleus

N10N11N12N13N14N15N16N17

HHeLiBeBCNOFNe
NaMgSiSArCaFeNiNdPb